Basic Maths Grand Test- Q9

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\lim_{x \rightarrow 0 }( \frac{(1-cos2x) (3+cosx)}{xtan4x} )   is equal to ?

asked Nov 17 in Basic Maths by gbmentor (85,520 points)
reshown Nov 20 by getgatebook

1 Answer

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ANS 2.

Divide and multiply by 4x in denominator.

Such that -       

____________Numerator__________

     X * tan4x  * 4x / 4x

Therefore tan4x/4x =1 

now we will have =  (1-cos2x) / 4x^2= (1-cos2x) / (2x)^2 = 1/2.

Now remaining is =   limit    ( 3+cosx)  * 1/2 = put x=0

So,    4/2=2

answered Nov 20 by bhargavakapilpro20 (13,760 points)
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