CO-Test 2-Question 9

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After completing current instruction at location 1000 the PC of a 16-bit processor 
points to next instruction which is JUMP 29. If position independent addressing scheme 
is employed and all numbers shown are in hexadecimal format, the content of 
PC (in octal) after executing this instruction is:—
asked Sep 29 in Computer Organization by getgatebook (36,710 points)
reshown Oct 13 by getgatebook

1 Answer

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PC at 1000 and the 16 bit processor is used for an instruction it means 2 bytes needed for 1 instruction.

When JUMP 29 instruction branched then PC = 1000+29 = 1029 in hexadecimal.

1029 in Octal =10051.
answered Oct 16 by dharmendratest (3,710 points)
Answer:
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